the bend moment M of a beam is given by dm/dx=w(1x) where w and l are constantsdetermine M in terms of x given that M=wl^2/2 plz show me working step Algebra Josephine solved a quadratic equation (x6)^2=49( x2 y2 ) dx 2xy dy = 0 ⇒dydx = y2 x22xy (1)It is a homogeneous differential equationLet y = vx (2) ∴dydx = v xdvdx (3) Substituting (2) and (3) in (1), we get v xdvdx = v2 x2 x22x vxv xdvdx = x2 (v2 1 )2vx2 = v2 12v2v2 2vx dvdx = v2 1 2vx dvdx = v2 12vv2 1 dv = dxx Integrating both sides, we get ∫2vv2 1 dv = ∫1x dxlog v2 1 = log x log Clog v2 1 =Expert Answer (According to Chegg policy only four subquestions will be answered Please post the remaining in another question) 2 dy/dx = x2y3/ (1x3) => dy (1/y3) = x2/ (1x3) dx Integrating both sides, view the full answer Previous question Next question

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(x^2-y^2)dx 2xydy=0 given that y=1 when x=1
(x^2-y^2)dx 2xydy=0 given that y=1 when x=1-Of the highest ordered derivative that appears in the given equation The degree of a differential equation is the degree of the highest ordered derivative treated as a variable I Examples (a) @2u @x2 @2u @y2 = 0 is of order 2 and degree 1 (b) (x2 y2)dx 2xydy = 0 is of order 1 and degree 1 (c) d3x dy3 2 x dx dy 4xy = 0 is of order 3 andAnswer to Solve the Ivp with y(1) = 8 and equation (x^2 y^2)dx 2xydy = 0 By signing up, you'll get thousands of stepbystep solutions to




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Answer to Solve the differential equation (1x^2)y' 2xy=0 Find solutions for your homework or get textbooks Search I'm at the beggining of a differential equations course, and I'm stuck solving this equation $$(x^2y^2)dx2xy\ dy=0$$ I'm asked to solve it using 2 different methods I proved I can find integrating factors of type $\mu_1(x)$ and $\mu_2(y/x)$If I'm not wrong, these two integrating factors are $$\mu_1(x)=x^{2} \ \ , \ \ \mu_2(y/x)=\left(1\frac{y^2}{x^2}\right)^{2}$$ The differential equations find the particular solution satisfying the given condition x^2dy (xy y^2) dx = 0;
Ex 95, 4 show that the given differential equation is homogeneous and solve each of them ( ^2 ^2 ) 2 =0 Step 1 Find / ( ^2 ^2 ) 2 =0 2xy dy = ( ^2 ^2 ) dx 2xy dy = ( ^2 ^2 ) dx / = ( ^2 ^2)/2 Step 2 Putting F (x, y) = / and finding F ( x, y) F (x, y) = ( ^2 ^2)/2 F ( x, y) = ( ( )^2 ( )^2)/ (2 )= ( ^2 ^2 ^2 ^2)/ ( ^22 )= ( ^2 ( ^2 ^2))/ ( ^22 ) = ( ^2 ^2)/2 = F (x, y) F ( x, y) = F (x, y) = F (x, y) Q The curve satisfying the differential equation , (x 2y 2) dx 2xy dy = 0 and passing through the point (1,1) is (a) an ellipse (b) a hyperbola (c)Free exact differential equations calculator solve exact differential equations stepbystep
(x 2 y 2) dx 2xydy = 0 It is a homogeneous differential equation Let y = vx(2) Substituting (2) and (3) in (1), we get Integrating both sides, we get It is given that when x = 1, y = 1 (1) 2 (1) 2 = C(1) C = 2 Thus, the required solution is y 2 x 2 = 2x OR It is a homogeneous differential equation Let y = vx(2)Uploaded By SicilianPenguin Pages 22 This preview shows page 16 out of 22 pages Solve the differential equation x(y1) dx(x1)dy=0 If y=2 when x=1 Latest Problem Solving in Differential Equations More Questions in Differential Equations Online Questions and Answers in Differential Equations



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The equation is a homogeneous equation Let y= vx, Differentiat ing wrt x, we get, `dy/dx=vx (dv)/dx` `dy/dx= (x^2y^2)/ (2xy) " from " (i)` `vx (dv)/dx= (x^2 (vx)^2)/ (2x (vx))` `vx (dv)/dx= (1v^2)/ (2v)` `x (dv)/dx= (1v^2)/ (2v)v` `x (dv)/dx= (1v^22v^2)/ (2v)`Solve the following differential equation (x2−y2)dx2xydy=0 given that \ ( y = 1 \) when \ ( x = 1 \) awsanket1176 is waiting for your help Add your answer and earn pointsSolve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and more




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Divide by x* (1y) and multiply by dx to get dy/ (1y)=dx/x and integrate both sides to get log (1y)=log (x)k1 then exponentiate to get 1y=k2*x so y=k2*x1 From this, dy/dx=k2 so x*dy/dx=x*k2=k2*x=1y=1k2*x1=k2*x which verifies the solution y=k2*x1 6 views1/2 (a) Find all equilibrium solutions (Your answer may depend on a) (b) Classify the equilibrium points using the linearization methodClick here👆to get an answer to your question ️ Solve the differential equation (x^2 y^2) dx 2xydy = 0



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SolutionShow Solution Given ( x2 − yx2 ) dy ( y2 x2y2 ) dx = 0 Dividing both the sides by \ dx\, we get \ \left ( x^2 y x^2 \right)\frac {dy} {dx} \left ( y^2 x^2 y^2 \right) = 0\ \ \Rightarrow x^2 \left ( 1 y \right)\frac {dy} {dx We can rearrange this Differential Equation as follows dy dx = − x2 y2 x2 − xy = − ( 1 x2)(x2 y2) ( 1 x2)(x2 −xy) = − 1 ( y x)2 1 − y x So Let us try a substitution, Let v = y x ⇒ y = vx Then dy dx = v x dv dx And substituting into the above DE, to eliminate y Solve (y√(x^2y^2))dxxdy=0 Latest Problem Solving in Differential Equations More Questions in Differential Equations Online Questions and Answers in Differential Equations




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Consider the family of nonlinear systems with parameter a given by dx/dt= x ay dy/dt= 4x2ay Suppose throughout that a >Calculus Find dy/dx y^2=1/ (1x^2) y2 = 1 1 − x2 y 2 = 1 1 x 2 Differentiate both sides of the equation d dx (y2) = d dx ( 1 1−x2) d d x ( y 2) = d d x ( 1 1 x 2) Differentiate the left side of the equation Tap for more steps Free Online Scientific Notation Calculator Solve advanced problems in Physics, Mathematics and Engineering Math Expression Renderer, Plots, Unit Converter, Equation Solver, Complex Numbers, Calculation History




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Solve ( x 2 y 2) dx 2xy dy = 0, given that y = 1, when x = 1 The answer given in the book is x 2 y 2 = 2xSolve the differential equation (x^2 y^2)dx 2xy dy = 0 ;The equation 2xydy (x^2 y^2 1)dx =0 can be rewritten as dy/dx y/2x = (1x^2)/2xy which is a Bernoulli equation To reduce it to normal form take y = U (x)^1/2 Then y' = (1/2) (U^1/2)U' and the equation becomes U' U/x = (1x^2)/x The integrating factor is 1/x and the solution is given




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Given that y = 1 when x = 1 12th Maths Ex 95, 12 For each of the differential equations in Exercises from 11 to 15 , find the particular solution satisfying the given condition 𝑥2𝑑𝑦 𝑥𝑦 𝑦2 𝑑𝑥=0;𝑦=1 When 𝑥=1 The differential equation can be written 𝑎s 𝑥2𝑑𝑦 = −(xy y2) dx 𝑑𝑦𝑑𝑥 = − 𝑥𝑦 𝑦2 𝑥2 LetSolve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and more




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Example 1 a If x 2 y 2 25 find dy dx b Find an equation of the tangent to the Example 1 a if x 2 y 2 25 find dy dx b find an School University of the Philippines Baguio;Find the corresponding particular solution for {eq}\displaystyle (x^2y^2)\ dx 2xy\ dy=0 {/eq} using the integrating factor Using an Integrating Factor The given equation is in the form of murshid_islam said If the boundary condition was , both and would be correct solutions, right?



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The differential equation is not well defined in (x,y) = (1,1) as you have an expression of the form 0/0 for dy/dx #8 murshid_islamY = 1 when x = 1 asked in Differential Equations by KumkumBharti ( 539k points)The solution of (dy/dx) = (x2 y2 1/2xy), satisfying y (1 Q The solution of d y d x = x 2 y 2 1 2 x y, satisfying y ( 1) = 0 is given by VITEEE VITEEE 14 Differential Equations Report Error A



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Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history y^2 = x^2(2lnx c) We can rewrite this Ordinary Differential Equation in differential form (x^2 y^2) \ dx xy \ dy = 0 A as follows \ \ \ \ dy/dx = (x^2 y^2)/(xy) dy/dx = x/y y/x B Leading to a suggestion of a substitution of the form u = y/x iff y = ux And differentiating wrt x whilst applying the product rule dy/dx = u x(du)/dx Substituting into the DE BCourse Title MATH 53;



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Factor out the Greatest Common Factor (GCF), 'dx' dx(1 y 2 1x 2) = 0 Subproblem 1 Set the factor 'dx' equal to zero and attempt to solve Simplifying dx = 0 Solving dx = 0 Move all terms containing d to the left, all other terms to the right Simplifying dx = 0 The solution to this equation could not be determined Solve the following differential equation (x^2 y^2 ) dx 2xy dy = 0 given that y = 1 when x = 1 Sarthaks eConnect Largest Online Education Community Given equation can be written as, ydx xdy2xy²dx x²ydy=0 Dividing both side by (xy)², we get d(xy)/(xy)² 2dx/x dy/y=0 Now it can be integrated easily



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Solution for (2xy)dx (x^21)dy=0 equation Simplifying (2xy) * dx (x 2 1) * dy = 0 Remove parenthesis around (2xy) 2xy * dx (x 2 1) * dy = 0 Multiply xy * dx 2dx 2 y (x 2 1) * dy = 0 Reorder the terms 2dx 2 y (1 x 2) * dy = 0 Reorder the terms for easier multiplication 2dx 2 y dy (1 x 2) = 0 2dx 2 y (1 * dy x 2 * dy) = 0 Reorder the terms 2dx 2 y (dx 2 y 1dy) = 0 2dx 2 y (dx 2 y 1dy) = 0 Combine like terms 2dx 2 y dxSolution for Solve dy/dx=2xy/(x^2y^2) Q A group of 150 tourists planned to visit East AfricaAmong them, 3 fall ill and did not come, of th A Consider the provided question, First draw the Venn diagram according to the given question, Let K rPopular Problems Calculus Find dy/dx 2xyy^2=1 2xy − y2 = 1 2 x y y 2 = 1 Differentiate both sides of the equation d dx (2xy−y2) = d dx (1) d d x ( 2 x y y 2) = d d x ( 1) Differentiate the left side of the equation Tap for more steps By the Sum Rule, the derivative of 2 x y − y 2 2 x y y 2 with respect to x x is d d x 2




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Solve both parts a and b as they are related Solve the given exact differential equations help_outline Image Transcription close (A) (xy)* dx (2xy x² –1)dy = 0, y (1) =1 fullscreenLearn how to solve differential equations problems step by step online Solve the differential equation xy*dx(1x^2)dy=0 Grouping the terms of the differential equation Group the terms of the differential equation Move the terms of the y variable to the left side, and the terms of the x variable to the right side Simplify the expression \frac{1}{y}dy Integrate both sides of the Get an answer for 'solve the differential equation (2xy3y^2)dx(2xyx^2)dy=0 ' and find homework help for other Math questions at eNotes




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(b) 2 x y dx ( y 2 x 2) dy = 0 Here, M = 2 x y, M y = 2x, N = y 2 x 2, and N x = 2 xNow, ( N x M y) / M = ( 2 x 2 x ) / ( 2 x y) = 2 / yThus, μ = exp ( ∫ 2 dy / y ) = y2 is an integrating factor The transformed equation is ( 2 x / y ) dx ( 1 x 2 y2) dy = 0 Let m = 2 x / y, and n = 1 x 2 y2Then, m y = 2 x y2 = n x, and the new differential equation is exact



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